Question

Three consecutive integers are such that when they are taken in increasing order and

multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers​

Answer 1

Answer:

7,8,9

Step-by-step explanation:

let the integers be,

x, x+1 and x+2

according to question,

2x+ 3(x+1) + 4(x+2)=74

2x+ 3x+ 3 + 4x + 8 = 74

9x= 74-11

9x = 63

x= 7

therefore, integers are 7, 8 ,9

this is the first question I am answering. Hope it helps...

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9