Question

Three consecutive integers are such that when they are taken in increasing order and

multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.​

Answer 1

Answer:

The numbers are 7,8,9.

Step-by-step explanation:

Let the three consecutive integers be x, x+1, x+2.

They are multiplied by 2,3,4 respectively and added to get 74.

2(x) + 3(x+1) + 4(x+2) = 74

2x + 3x + 3 + 4x + 8 = 74

9x + 11 = 74

9x = 63

x = 63/9

x = 7

Therefore the numbers are 7,8,9

Source: From one of my answers to the same question.

Answer 2

Let the three consecutive integers are x, x+1 and x+2.

So, According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9