Question

Three consecutive integers are such that when they are taken in increasing order and

multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.​

Answer 1

Answer:

7, 8, 9

Step-by-step explanation:

The integers are: x-1, x and x+1 in increasing order

Multiplied and added up as:

2(x-1)+3x+4(x+1)=74

2x-2+3x+4x+4=74

9x=72

x=8

So the Integers are: 7, 8 and 9

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Answer 2

Let the three consecutive integers are x, x+1 and x+2. According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9