Question

three consecutive integers are such that when they are taken increasing order and multiple by two three and four respect leave they add up to 74 find these numbers

Answer 1

the no. are 7 8 and 9

Answer 2

Answer:

7, 8 and 9

Step-by-step explanation:

Let the integers be x, x +1, and x + 2.

So, According to the question,

=> 2x + 3(x + 1) + 4(x + 2) = 74

=> 2x + 3x + 3 + 4x + 8 = 74

=> 9x + 11 = 74

=> 9x = 74 - 11

=> 9x = 63

=> x = 63/9

=> x = 7

So, the integers are -

• x = 7
• x + 1 = 7 + 1 = 8
• x + 2 = 7 + 2 = 9