Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 74. Find the numbers
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Hlohlohlohlo
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Here's your answer
Let the numbers be x, x+1, x+2
By the given conditions,
2(x) + 3(x+1) + 4(x+2) = 74
2x+3x+3+4x+8 = 74
9x+11 = 74
9x = 63
x = 63/9 = 7
x = 7
Hence the numbers are 7, 8 and 9
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