Question

three consecutive integers are such that when they are taken in increasing order multiplied by 2,3and 4 respectively then add up to 74 find these numbers ​

Answer 1

Answer:

let the 1st integer be x

then next integers are x+1,x+2.

now

(x)*(2)+(x+1)*(3)+(x+2)*(4)=74

2x+3x+3+4x+8=74

9x+11=74

9x=74-11

x=63/9

x=7

Numbers are 7,8 and 9

Step-by-step explanation:

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9