three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 respectively, they add up to 74.Find the number.
Answers
Answered by
0
Step-by-step explanation:
Let 3 consecutive integers: x,x+1,x+2
As per the question: 2x+3(x+1)+4(x+2)=74
9x+11=74
Transpose 11 to RHS
9x=63
Divide both sides by 9
x=
9
63
,x=7
x=7,
x+1=7+1=8
x+2=7+2=9
Numbers are 7,8 and 9
Answered by
0
Answer:
7, 8, 9
Step-By-Step Explanation:
Let the three consecutive integers are x, x+1 and x+2.
According to the question,
2x + 3(x+1) + 4(x+2) = 74
⇒ 2x + 3x +3 + 4x + 8 = 74
⇒ 9x + 11 = 74
⇒ 9x = 74 – 11
⇒ 9x = 63
⇒ x = 63/9
⇒ x = 7
Thus, the numbers are:
x = 7
x + 1 = 8
x + 2 = 9
Similar questions