three consecutive integers are such that when they are taken in increasing order multiplyed by 2,3 and 4 respectively they added up to 74 find these numberes
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Answer:
7, 8 and 9
Step-by-step explanation:
Let the consecutive integers be x, x + 1, x + 2.
According to the question,
=> 2x + 3(x + 1) + 4(x + 2) = 74
=> 2x + 3x + 3 + 4x + 8 = 74
=> 9x + 11 = 74
=> 9x = 74 - 11
=> 9x = 63
=> x = 63/9
=> x = 7
So, the integers are:
=> x = 7
=> x + 1 = 7 + 1 = 8
=> x + 2 = 7 + 2 = 9
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