Question

Three consecutive integers are such that
when they are taken in increasing order
and multiplied by 2, 3 and 4 respectively​

Answer 1

Answer:

heya mate

The three consecutive integers to be x,x+1,x+2

So ,

Let's multiply the three integers with 2,3 and4

By multiplying we get

x*2=2x

(x+1)*3= 3x+3

(x+2)*4=4x+8

Add these

2x+3x+3+4x+8= 74

(2x+3x+4x) (3+8)

9x +11 =74

9x=74-11

9x=63

x= 63/9

x=7

The three consecutive integers are

x= 7

x+1=8

x+1= 9

Step-by-step explanation:

I hope it helps you

Answer 2

Answer:

8th question's answer is:- for example if the integers are 1,2,3 then they will be multiplied respectively to 2,3,4. In the same way, the numbers will be x , x+1 and x+2 but as they are being multiplied by 2,3, and 4. therefore the way we will have to solve this question will be:-

2(x) + 3(x+1) + 4(x+2) = 74

2x + 3x+3 + 4x+8 = 74

(2x+3x+4x) + 3+8 +74

9x + 11 =74

9x=74-11

9x= 63

x=63/9 = 7

x=7

2(x) = 2*7 = 14

3(x+1) = 3(7+1) = 3*8 = 24

4(x+2) = 4(7+2) = 4*9 = 36

therefore the integers are 14, 24 and 36

we can even check this answer:- 14+24+36= 74

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