Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 respectively, they add up to 74. find these numbers​

Answer 1

Answer:

7 , 8 , 9

Step by Step answer

Let the three consecutive integers be x, x+1, x+2 in increasing order

Multiply 2,3,4 respectively

2(x)+3(x+1)+4(x+2)

This adds up to 74

2(x)+3(x+1)+4(x+2)=74

2x+3x+3+4x+8=74

9x+11=74

9x=74-11=63

X=63÷9=7

Therefore the three consecutive integers are 7,8,9

Answer 2

Step-by-step explanation:

let the number be x

(X*2)+ (X+1*3)+(X+2*4)=74

2x+(3x+3)+(4x+8)=74

9x+11=74

9x=74-11

9x=63

then X=7

hence the consecutive integers are 7,8 and 9

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