Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 56. Find these numbers.​

Answer 1

Answer:

let the 3 consecutive integers be x , x+1, x+2

they are multiplied by 2,3 and 4 respectively to give 56.

2x + 3(x+1) + 4(x+2) = 56

2x + 3x + 3 + 4x + 8 = 56

9x + 11 = 56

9x = 45

x = 45/9

x = 5

so the consecutive integers are 5, 6 and 7.

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