Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 3,4,and 5 respectively ,they are add up upto 84 ,find these number​

Answer 1

Answer:

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 74.

Solution :

Let us assume the three consecutive integers to be x, x+1 and x+2.

So,

Let us multiply the three integers with 2,3 and 4 respectively,

we get,

⇒ x*2 = 2x

⇒ (x+1)*3 = 3x + 3

⇒ (x+2)*4 = 4x + 8

Now adding 1, 2 and 3 we get ,

2x +3x+3 +4x+8 =74

9x+11 = 74

9x =74-11      

x = 63/9

x = 7

So,

the three integers are,

x=7

x+1 = 8

x+2 = 9

Step-by-step explanation:

Answer 2

Answer:

Three consecutive integers are such that, when they are taken in increasing order and multiplied by 2, 3, and 4, respectively, they add up to 74. How would one find these numbers?

Master's in Electric Vehicle Design & Analysis.

Three consecutive integers are such that, when they are taken in increasing order and multiplied by 2, 3, and 4, respectively, they add up to 74. How would one find these numbers?

Consecutive numbers are numbers that follow each other in order. They have a difference of 1 between every two numbers.

Let the smallest of consecutive integer be n,

Therefore, other two consecutive integers are to be n + 1 and n + 2 in increasing order

Now multiplying these three consecutive numbers with 2, 3, and 4 respectively. They become

2 (n), 3 (n + 1) and 4 (n + 2)

These add up to 74, means

2 (n) + 3 (n + 1) + 4 (n + 2) = 74

2n + 3n + 3 + 4n + 8 = 74

9n + 11 = 74

9n = 74 - 11

9n = 63

n = 63/9

n = 7

The smallest consecutive Integer is 7, therefore other two consecutive integers are:

7 + 1 = 8

7 + 2 = 9

Thus the three consecutive integers are 7, 8 and 9