Question

three consecutive integers are such that when they are taken into increasing order and multiplied by 2 3 and 4 respectively they added up to 74 find the number​

Answer 1

Step by Step *Explanation*

Answer:

Let the number be y so the consecutive numbers will be y+1 y+2 y+3 . Then we should multiply it by 2 3 and 4

so

2(y+1) + 3(y+2) + 4(y+3) = 74

let's open up the brackets

(2×y+2×1) + (3×y+3×1) (4×y+4×1)

(2y+2) + (3y+3) + (4y+4)

And let's make all the y's together and the numbers seperate let's sort it out

9y + 9 = 74

9y = 74-9=65

y = 65÷9

y= 65/9

Answer 2

Answer

Given:

• Three consecutive integers are taken in increasing order and multiplied by 2, 3 and 4 respective.

• The number add up to 74

Asked:

Find these number

Unknown:

• Let the number be x, x + 1 and x + 2

• (because these are conseative in integers)

• they are taken increasing order and multiplied by 2, 3 and 4 respectively

so x becomes 2x

(x + 1) becomes 3(x + 1)

(x + 2) becomes 4(x + 2)

2x + 3(x + 1) + 4(x + 2) = 74

2x + 3x + 3 + 4x + 8 = 74

9x + 11 = 74

9x = 74 - 11

9x = 63

x = 63/9

x = 7

Therefore:

The value of x = 7.