Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4respectively they add upto 101. Find the number​

Answer 1

Step-by-step explanation:

Let x, x+1, x+2 be the consecutive integers.

2x + 3(x+1) + 4(x+2) = 101

2x+3x+3+4x+8 = 101

(2x+3x+4x)+(3+8) = 101

9x + 11 = 101

9x = 101 - 11

9x = 90

x = $\frac{90}{9}$

x = 10

Since, x = 10, the three integers are 10, 11 and 12

Check:

2 x 10 + 3 x 11 + 4 x 12 = 101

20 + 33 + 48 = 101

101 = 101

Conclusion:

Hence, proved