Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.

Answer 1

Answer:

7,8,9

Step-by-step explanation:

let one no be x

then second no = x+1

third no= x+2

according to question,

2x + 3(x+1) + 4(x+2) = 74

= 2x+3x+3+4x+8 = 74

= 9x+11 = 74

= 9x = 74-11

= 9x = 63

then x= 63/9 = 7

so first no = x= 7

so first no = x= 7second no = x+1 = 7+1 = 8

so first no = x= 7second no = x+1 = 7+1 = 8third no = x+2 = 7+2 = 9

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Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9