Three consecutive integers are such that when they are taken in increasing order and multiplied by 3, 4 and 5 respectively, they add up to 386. Find these numbers.
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Answer:Let the consecutive numbers be x, x +1 and x + 2
Multiplied by 3, 4, and 5 respectively, The numbers will become
3(x) = 3x
4(x + 1) = 4x + 4
5(x + 2) = 5x + 10
Sum of these numbers = 386
3x + 4x + 4+ 5x + 10 = 386
12x + 14 = 386
12x = 386-14
x = 31
So numbers are 31,32,33.
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