Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 respectively,they add upto 74. find these nos. ?

Answer 1

let the first ,second and third number be x,x+1,x+2 respectively.
Multiplied by 2,3,4 respectively = 2x,3x+3,4x+8
Sum = 74
2x+3x+3+4x+8=74
9x+11=74
9x = 63
x = 7
The consecutive numbers are 7x,8(x+1) and 9(x+2)

Answer 2

$\bold \: here \: is \: your \: answer$
let the required no.be x,x+1and x+2.

2*x+3(x+1)+4(x+2)=74

2x+3x+3+4x+8=74

9x +11=74

9x=74-11

9x=63

x=63/9

x=7

the required no. are 7,7+1=8,7+2=9