Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2 3 and 4 the add up to respectively 74. Find the numbers

Answer 1

Let three consecutive integers be x, (x+1) and (x+2).
According to question (A.T.Q)
x*2+(x+1)*3+(x+2)*4=74
=>2x+3x+3+4x+8=74
=>9x+11=74
=>9x=74-11
=>9x=63
=>x=63/9=7
.
. . other integers are—>
x+1=7+1=8
x+2=7+2=9
hence three integers are 7,8and9

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9