Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4
respectively, they add up to 74. Find these
numbers​

Answer 1

Answer:

Let 1 integer = X

let second integer = X+1

let 3rd integer = X+2

now ...if 1st integer= 2x

2nd integer= 3(X+1)

3rd integer= 4(X+2)

their sum = 74

according to question...

2x+ 3(X+1)+4(X+2)= 74

2x+3x+3+4x+8= 74

9x+11= 74

9x= 74-11

9x= 63

X= 63/9

X= 7

so.. 1st no. = 7

2nd no. 7+1= 8

3rd no. = 7+2= 9

hope it helps..