Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.​

Answer 1

Answer:

Let the three consecutive integers be n,n+1,n+2 respectively.

According to the problem,

2n+3(n+1)+4(n+2)=74

or, 9n+11=74

or, 9n=63

or, n=7.

So the numbers are 7,8,9.

Answer 2

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→ Given Question:-

→ Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 74. Find these numbers.

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→ Solution:-

⇒  Let The tree consecutive integers be →

⇒  x , x + 1 , x +2

⇒  As in the given in the Question

⇒ 2x + 3(x + 1 ) + 4 (x + 2) = 74

⇒ Add it

⇒ 2x + 3x + 3 + 4x + 8 = 74

⇒ 9x + 11 =  74

⇒ 9x = 74 - 11

⇒ x = $\frac{63}{9}$

⇒ x= 7

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⇒ Now , we should find the numbers →

⇒ x , x + 1 , x + 2

⇒ x = 7 , as we found it.

⇒ x + 1 = 7 + 1  = 8

⇒ x + 2 = 9

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→ Similar Question:-

⇒ Three consecutive integers are such that when they are taken in increasing order and multiplied by 3, 2, and 5 respectively, they add up to 46. Find these numbers.​

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