Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers. please tell in a short and easy way
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Answered by
1
Answer:
Let the three consecutive integers be x, x+1, and x+2.
According to the question, 2x+3(x+1)+4(x+2)=74
\Rightarrow\ 2x+3x+3+4x+8=74⇒ 2x+3x+3+4x+8=74
\Rightarrow\ 9x+11=74⇒ 9x+11=74
\Rightarrow\ 9x+11-11=74-11⇒ 9x+11−11=74−11
[Subtracting 11 from both sides]
\Rightarrow\ 9x=63⇒ 9x=63
\Rightarrow\ \frac{9x}{9}=\frac{63}{9}⇒
9
9x
=
9
63
[Dividing both sides by 9]
x = 7
Hence first integer = 7, second integer
= 7 + 1 = 8 and thirs integer = 7 + 2 = 9
Step-by-step explanation:
Answered by
1
7 and 8 and 9
Step-by-step explanation:
let the numbers be x (x+1) (x+2)
then 2×x+3(x+1)+4(x+2)=74
2x+3x+3+4x+8=74 ( opening brackets)
9x+11 =74
9x=74-11
9x=63
x=63/9
x=7
x+1= 7+1
=8
x+2 =7+2
=9
the three consecutive numbers are 7 and 8 and 9
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