Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 74.Find these numbers​

Answer 1

Let the smallest integer be x.
The numbers are x, x+1 and x+2.
Given that
2x + 3(x+1) + 4(x+2) = 74
or, 2x + 3x + 3 + 4x + 8 = 74
or, 9x + 11 = 74
or, 9x = 74 - 11
or, 9x = 63
or, x =7

Hope it helps!

Answer 2

Let the three integars be x,x+1,x+2

•then according to question-:

$2x + 3(x + 1) + 4(x + 2) = 74$

$2x + 3x + 3 + 4x + 8 = 74$

$9x + 11 = 74$

$9x = 74 - 11$

$9x = 64$

$x = 63 \div 9$

$x = 7$

so,the first integer =7

second integer=(x+1)=7+1=8

third integar = (x+2)=7+2=9