three consecutive Integers are such that when they are taken in increasing order and multiplied by 2,3,4 respectively, they add up to 14. find these numbers
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Answer:
Step-by-step explanation:
Let the three consecutive integers be x, x+1, and x+2.
According to the question, 2x+3(x+1)+4(x+2)=74
\Rightarrow\ 2x+3x+3+4x+8=74⇒ 2x+3x+3+4x+8=74
\Rightarrow\ 9x+11=74⇒ 9x+11=74
\Rightarrow\ 9x+11-11=74-11⇒ 9x+11−11=74−11
[Subtracting 11 from both sides]
\Rightarrow\ 9x=63⇒ 9x=63
\Rightarrow\ \frac{9x}{9}=\frac{63}{9}⇒
9
9x
=
9
63
[Dividing both sides by 9]
x = 7
Hence first integer = 7, second integer
= 7 + 1 = 8 and thirs integer = 7 + 2 = 9
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