Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
Answers
Step-by-step explanation:
numbers be n-1, n, n+1
2(n-1)+3n+4(n+1)=74
2n+3n+4n+2=74
9n=72
n=8
numbers are 7,8,9
Answer:
The three consecutive integers are 7, 8 and 9.
Step-by-step explanation:
Let the first integer be x.
Then, second integer will be x + 1.
And, the third integer will be x + 2.
After taking in increasing order,
x × 2 = 2x (I)
(x + 1) × 3 = 3x + 3 (II)
(x + 2) × 4 = 4x + 8 (III)
Now, adding equations (I), (II) and (III),
2x + 3x + 3 + 4x + 8 = 74
9x + 11 = 74
9x = 74 - 11
9x = 63
x = 63 ÷ 9
•°• x = 7
Finally,
First integer = x = 7
Second integer = x + 1 = 7 + 1 = 8
Third integer = x + 2 = 7 + 2 = 9
Hence, the three consecutive integers are 7, 8 and 9.
Adiós! Hope this helps you.