Three consecutive integers are such that when they are taken in increasing order and
multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers
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Let the three consecutive integers be n, n+1, n + 2 respectively.
According to the problem,
2n + 3(n+1) + 4(n + 2) = 74
or, 9n+ 11 = 74
or, 9n = 63
or, n = 7.
So the numbers are 7, 8, 9.
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