Question

three consecutive integers are such that when they are taken in increasing order and multiplyed by 2,3 and 4 respectively they add upto 74. find the numbers​

Answer 1

$\huge\underline\mathtt\red{Answer:}$

$\color{blue}Let 3 \: consecutive \: integers:$

x, x+1, x+2

As per the question:

$2x + 3(x + 1) + 4(x + 2) = 74$

9x + 11 = 74

Transpose 11 to RHS

9x = 63

Divide both sides by 9

$x = \frac{63}{9},x = 7$

x = 7

x + 1= 7 + 1 = 8

x + 2 = 7 + 2 = 9

$\color{Green}The \: Numbers \: are \: 7 ,\: 8 ,\: 9$