Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively , they add up to 74. Find these numbers. (STD 8). Plzzz answer it fast....URGENT!!!....

Answer 1

let the numbers be X,X+1,x+2
therefore new numbers are 2x,3x+3,4x+8
given 2x+3x+3+4x+8=74
so X=7
so integers are 7,8,9

Answer 2

Heyaa..!

Let the three consecutive integers be x, x + 1, x + 2


As per the question..

2 x + 3 ( x + 1 ) + 4 ( x + 2 ) = 74

2x + 3x + 3 + 4x + 8 = 74

9x + 11 = 74

9x = 74 - 11

x = 63 / 9

x = 7

Therefore the consecutive integers are 7, 8, 9

Hope it helps..!

And here CutieBarbie :)