Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
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Answers
Let the three consecutive integers be x, x + 1 and x + 2.
As per the condition, we have
2x + 3(x + 1) + 4(x + 2) = 74
⇒ 2x + 3x + 3 + 4x + 8 = 74
⇒ 9x + 11 = 74
⇒ 9x = 74 – 11 (transposing 11 to RHS)
⇒ 9x = 63
⇒ x = 63 ÷ 9
⇒ x = 7 (transposing 7 to RHS)
Thus, the required numbers are 7, 7 + 1 = 8 and 7 + 2 = 9, i.e., 7, 8 and 9.
Answer:
Giνєn :
- ➤ Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively.
- ➤ The sum of consecutive numbers is 74.
To Fiηd :
- ➤ The numbers
Concєpt :
» Here, the three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74.
» So, let the consecutive numbers be x, (x+1), (x+2).
Solυtioη :
★ The consecutive numbers are taken in increasing order and multiplied by 2, 3 and 4 respectively. So,
∴ The value of x is 7.
✴ First consecutive number -
∴ First consecutive number is 14.
✴ Second consecutive number -
∴ Second consecutive number is 24.
✴ Third consecutive number -
∴ Three consecutive number is 36.
Vєrificαtioη :
Hence Verified!
Ansωєr :
- ➤ The three consecutive numbers are 14, 24 and 36.
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