Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
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Answer:
It is given that the three consecutive integers multiplied by 2, 3, and 4 respectively, add up to 74. Therefore, the smallest consecutive integer out of the three numbers is 7. Therefore, the three consecutive integers are 7, 8, and 9.
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Answer__verified by topper
Let the three consecutive integers are x, x+1 and x+2.
According to the question,
2x + 3(x+1) + 4(x+2) = 74
⇒ 2x + 3x +3 + 4x + 8 = 74
⇒ 9x + 11 = 74
⇒ 9x = 74 - 11
x= 63/9
⇒ x = 7
Thus, the numbers are:
x = 7
x+1 = 8
x+2 = 9
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