Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
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Answer:
They are 7, 8 and 9.
Step-by-step explanation:
If the 3 numbers are x, x+1 and x+2
2x + 3(x + 1) + 4(x + 2) = 74
2x + 3x + 3 + 4x + 8 = 74
2x + 3x + 4x + 11 = 74
9x = 74 - 11 = 63
x = 63/9 = 7.
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