Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.


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Answer 1

Answer:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 - 11

\Rightarrow x=\frac{63}{9}⇒x=

9

63

⇒ x = 7

Thus, the numbers are:

x = 7

x+1 = 8

x+2 = 9

hope it's help you

Answer 2

Let 3 consecutive integers: x,x+1,x+2

As per the question: 2x+3(x+1)+4(x+2)=74

9x+11=74

Transpose 11 to RHS

9x=63

Divide both sides by 9

x= 63/9,x=7

x=7,

x+1=7+1=8

x+2=7+2=9

Numbers are 7,8 and 9

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