Question

Three consecutive integers are such that when they are taken in increasing order and multipled by 3,4,and 5 respectively they are up to 386 find these numbers

Answer 1

let the integers be x,x+1,x+2


3×x+4 (x+1)+5 (x+2)

3x+4x+4+5x+10=386
12x=386-14
x=372/12
x=31

Hence numbers are 31,32,33