Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2 , 3 and 4 they add up to 74 find these this numbers

Answer 1

let the three consecutive integers are ,x , x + 1 , and x + 2

according to question ,

2(x ) + 3 ( x + 1 ) + 4 ( x + 2) = 74

2x + 3x + 3 + 4x + 8 = 74

9x = 74 - 11

9x = 63

x = 7

hence, these three consecutive integers are

x = 7

x + 1 = 7 + 1 = 8

x + 2 = 7 + 2 = 9

Answer 2

Here is your Answer

Let the First Number be x

∴ As per Question

2x + 3x+3 + 4x + 8 = 74

9x + 11 = 74

9x = 63

x = 63/9

x = 7

First Number=x=7

Second Number=x+1=8

Third Number=x+2=9

Hope it Helps