Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively..they add up to 74.Find the numbers......plzz ans. Fast its urgent!!!!

Answer 1

Answer:Three consecutive integers are 7,8 and 9

Solution:

Let the numbers are x, x+1 and x+2

(Since these are consecutive integers)

they are taken in increasing order and multiplied by 2,3 and 4 respectively

So x becomes 2x

(x+1) becomes 3(x+1)

(x+2) becomes 4(x+2)

they add up to 74,so ATQ

$2x + 3(x + 1) + 4(x + 2) = 74 \\ \\ 2x + 3x + 3 + 4x + 8 = 74 \\ \\ 9x + 11 = 74 \\ \\ 9x = 74 - 11 \\ \\ 9x = 63 \\ \\ x = \frac{63}{9} \\ \\ x = 7$
So,

Integers are 7,8,9

Verification:

$2 \times 7 + 3 \times 8 + 4 \times 9 \\ \\ = > 14 + 24 + 36 \\ \\ = >7 4$
Hence the calculate integers are correct.

Hope it helps you.

Answer 2

Given :

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 74.

Solution :

Let us assume the three consecutive integers to be x, x+1 and x+2.

So,

Let us multiply the three integers with 2,3 and 4 respectively,

we get,

⇒ x*2 = 2x

⇒ (x+1)*3 = 3x + 3

⇒ (x+2)*4 = 4x + 8

Now adding 1, 2 and 3 we get ,

2x +3x+3 +4x+8 =74

9x+11 = 74

9x =74-11      

x = 63/9

x = 7

So,

the three integers are,

x=7

x+1 = 8

x+2 = 9