Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively they add up to 74 find those numbers intext:zigya
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1st integer =x
2nd integer =x+1
3rd integer =x+2
multiplied we get
1st integer =2x
2nd integer=3x+3
3rd integer =4x+8
ATQ
2x+3x+3+4x+8 = 74
9x+11=74
9x=74-11
x=63/9
x=7
1st integer =x=7
2nd integer=x+1=7+1=8
3rd integer = x+2=7+2=9
2nd integer =x+1
3rd integer =x+2
multiplied we get
1st integer =2x
2nd integer=3x+3
3rd integer =4x+8
ATQ
2x+3x+3+4x+8 = 74
9x+11=74
9x=74-11
x=63/9
x=7
1st integer =x=7
2nd integer=x+1=7+1=8
3rd integer = x+2=7+2=9
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