Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 they add up to 74 find the no.

Answer 1

let the first no be X,
so 1st no.- X
2nd no.- x+1
3rd no. - x+2
these nos. are in increasing order
so,

so,1st no. -2x
2nd no. -3(X+1)
3rd no. -4(X+2)


so, 2x+3(X+1)+4(X+2) = 74
or, 2x + 3x+ 3+4x+8= 74
or, , 2x + 3x+4x+11= 74
or 9x= 74-11= 63
or 9x= 63
or, X= 7


so,1st no. -2x= 14
2nd no. -3(X+1)=3*8=24
3rd no. -4(X+2)=4*9= 36