three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 they add up to 74 find the no.
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Let the integers be x, x+1, x+2
According to question
2x+3(x+1)+4 (x+2)=74
2x+3x+3+4x+8=74
9x+11=74
9x=74-11
9x=63
x=63/9
x=7
Required integers are 7,8,9.
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