Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 respectively, they add up to 74. find these numbers​

Answer 1

Let these Three consecutive numbers are X, Y, and Z.
so Y = X+1, and Z = Y+1 = X+2
A/q,
        2X+3Y+4Z = 74
OR,  2X+3(X+1)+4(X+2) = 74
OR,  2X+3X+4X+3+8 = 74
OR,   9X = 74-11
OR,    X = 63/9 = 7
Therefore numbers are X = 7, Y = 7+1 = 8, and Z = 8+1 = 9

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9