Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 respectively, they add up to 74. find these numbers
Answers
Answered by
9
Let these Three consecutive numbers are X, Y, and Z.
so Y = X+1, and Z = Y+1 = X+2
A/q,
2X+3Y+4Z = 74
OR, 2X+3(X+1)+4(X+2) = 74
OR, 2X+3X+4X+3+8 = 74
OR, 9X = 74-11
OR, X = 63/9 = 7
Therefore numbers are X = 7, Y = 7+1 = 8, and Z = 8+1 = 9
so Y = X+1, and Z = Y+1 = X+2
A/q,
2X+3Y+4Z = 74
OR, 2X+3(X+1)+4(X+2) = 74
OR, 2X+3X+4X+3+8 = 74
OR, 9X = 74-11
OR, X = 63/9 = 7
Therefore numbers are X = 7, Y = 7+1 = 8, and Z = 8+1 = 9
Answered by
1
Answer:
7, 8, 9
Step-By-Step Explanation:
Let the three consecutive integers are x, x+1 and x+2.
According to the question,
2x + 3(x+1) + 4(x+2) = 74
⇒ 2x + 3x +3 + 4x + 8 = 74
⇒ 9x + 11 = 74
⇒ 9x = 74 – 11
⇒ 9x = 63
⇒ x = 63/9
⇒ x = 7
Thus, the numbers are:
x = 7
x + 1 = 8
x + 2 = 9
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