Three consecutive integers are such that when they are taken in increasing order and are multiplied by 2,3 and 4 respectively, they add up to 74 . Find these numbers
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Ist consecutive integer=2(x)
2nd consecutive integer=3(x+1)
3rd consecutive integer=4(x+2)
A.T.Q.=2(x)+3(x+1)+4(x+2)=74
=2x+3x+3+4x+8=74
=9x+11=74
=9x=74 -11
=9x = 63
=x = 63/9
=x=7
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