Question

three consecutive integers are such that when they are taken in increasing orders and multiplied by the 2,3,and 4 respectively this add up to 74. find the numbers ​

Answer 1

Answer:

The Three consecutive numbers are 7, 8 and 9.

Step-by-step explanation:

Suppose the numbers are a, a+1 and a+2

According to given condition;

2(a) + 3(a+1) + 4(a+2) = 74

2a + 3a + 3 + 4a + 8 = 74

9a + 11 = 74

9a = 74 - 11

9a = 63

a = 63/9

a = 7

The three consecutive numbers are hence written as;

a = 7

a + 1 = 8

a + 2 = 9

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9