Question

three consecutive integers are such that when they were taken in increasing order and multiplied by 2 3 and 3 respectively they add up to 74 find these numbers​

Answer 1

Step-by-step explanation:

Let the smallest integer be x

First consecutive integer is x+ 1

Second consecutive integer is x + 2

Multiplied by 2(x), 3(x+1), 4(x+2)

According to the question 2(x) +3(x+1)+4(x+2) = 74

2x+3x+3+4x+8= 74

9x+11= 74

9x =74-11

9x = 63

x= 63/9

x=7

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Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9