Question

three consecutive integers are such when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 56 find these numbers. please explain it properly.....​

Answer 1

Answer:

Let the integer be x

2nd integer = x+1

3rd integer = x+2

A.T.Q.

2(x)+3(x+1)+4(x+2)=56

2x+3x+3+4x+8=56

9x+11=56

9x=56-11

9x=45

x=45/9

x=5

x+1=6

x+2=7

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Answer 2

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