Question

Three consecutive integers are taken so x^2 + (x+1)(x+2)=154. Find the integers

Answer 1

this is the answer. the numbers are 8,9 and 10

Answer 2

Answer: let three consecutive positive integers

= x,x+1,x+2

so, x²+(x+1)(x+2) = 154

= x²+x²+2x+x +2= 154

2x²+3x-152= 0

= 2x²+19x-16x-154=0

( x-8)(2x+19)

x= 8

so, x+1 = 9

x+2= 10 ans.

so, the multiple of 3 is 9

so, the integer is x+1ans.

answer➡ 8,9,10.

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