Question

Three consecutive integers have a sum of 123

Answer 1

HI MATE!!!

(X+1)+(X+2)+(X+3)=123

3X+6=123

3X=123-6
3X=117
X=117/3
X=39
THE CONSECUTIVE NUMBERS ARE
X+1=40
X+2=41
X+3=42
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BYE MATE!!!

Answer 2

Let the three consecutive integers be (x-1),x & (x+1).

As per given condition,

x-1+x+x+1 = 123

3x = 123

x = 41

Hence the integers are,

x-1 = 41-1 = 40

x = 41

x+1 = 41+1 = 42