Question

Three consecutive integers have a sum of 216 . Find the integers.

Answer 1

let three consecutive integers n,n+1 and n+2
According to question
n+n+1+n+2=216
3n+3=216
3n=216-3
3n=213
n=213/3
n=71

so, n=71
therefore,three integers are
n=71
n+1=71+1=72
n+2=71+2=73
71,72 and 73 are the three integers