Math, asked by kenyalashawn12, 11 months ago

Three consecutive integers have a sum of 51.

Answers

Answered by saurabh3j
1

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17

18

19

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Answered by Anonymous
12

Step-by-step explanation:

we have to prove:

n+(n+1)+(n+2)=51

to find n

3n+3 =51

3n=51-3

3n=48

n=48/3

n=16

so take L.H.S and

put n= 16

(16)+(16+1)+(16+2)

16+17+18

51

WHICH IS EQUALTO R.H.

S

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