Question

Three consecutive integers have an interesting relationship. The sum of 8 times the middle and 5 times the largest equals 12 times the smallest integer. Determine the integers.

Answer 1

Step-by-step explanation:

let the consecutive integers be X, X+1 and X+2.

:. according to question, we have:

8(X+1) + 5(X+2) = 12x

=> 8x+8+5x+10 = 12x

=> 8x+5x+10+8 = 12x

=> 13x-12x = -18

=> x = -18

therefore, we have:

1st number = X = -18

2nd number = X+1 = -18+1 = -17

3rd number = X+2 = -18+2 = -16

therefore, the triplet is : -18, -17, -16

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