Question

three consecutive integers such that the middle number exceeds the difference of the squares of the other twoby 60

Answer 1

Answer:

Step-by-step explanation:

let the integers be x, x+1,x+2

by data x+1+60=(x+2)(x+2)-x2

             x+61=x2+2x+4-x2

                 x+61=2x+4

                    57=2x-x

                      x=57

              therefore the consecutive numbers are 57,58,59