Question

three consecutive integers such that when there is they are taken in increasing order and X 2 3 and 4 respectively they are headed up to 74 find this number

Answer 1

Let the no be x, x+1,x+2 Atq 2x+3(x+1)+4(x+2)= 72 2x+ 3x+3 +4x+8=72 9x+11= 72 9x=72-11=61 x=61÷9