Question

three consecutive integers such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. find these numbers​

Answer 1

Answer:

Let the First, number be x.

Then, Next number will be x + 1

Then, Next number will be x + 2

Therefore, 2(x) + 3(x + 1) + 4(x + 2) = 74

2x + 3x + 3 + 4x + 8 = 74

9x + 11 = 74

9x = 74 - 11

9x = 63

x = 63

9

x = 7

So, the numbers are 7, 7+1, 7+2.

that is= 7,8 and 9.

HOPE IT WILL HELP YOU.

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9